Can you order the digits 1,2,3,4,5 and 6 tomake a number which is divisible 6...
..so that when the final or last digit is removed again it becomes a 4 -figure number divisible by 4when the final or last digit is removed again it becomes a 3 -figure number divisible by 3when the final or last digit is removed again it becomes a 2-figure number divisible by 2 then finally a 1 figure number divisible by 1?