When applying our model on a continuous
sound wave (as opposed to a single pulse situation),
one should take into account the resonance
phenomenon. This means that for input sounds
of half-wavelength, which is about the size of a
stethoscope, we might get a resonance that will
cause the sound amplification to be of a much
higher magnitude than the one predicted by
equation (12). Let us demonstrate this point by
considering one possible resonance mode, generated
by a standing sound wave formed along the
main symmetry axes of a stethoscope funnel. In
this case one may consider the stethoscope as an
open-ended tube of length h. Therefore, the resonant
frequencies are given by [5, 11]:
When applying our model on a continuoussound wave (as opposed to a single pulse situation),one should take into account the resonancephenomenon. This means that for input soundsof half-wavelength, which is about the size of astethoscope, we might get a resonance that willcause the sound amplification to be of a muchhigher magnitude than the one predicted byequation (12). Let us demonstrate this point byconsidering one possible resonance mode, generatedby a standing sound wave formed along themain symmetry axes of a stethoscope funnel. Inthis case one may consider the stethoscope as anopen-ended tube of length h. Therefore, the resonantfrequencies are given by [5, 11]:
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