as illustrated in Table 2. Then the negative Di or Dj having largest absolute value is selected, as in Table 2. Here the transformation which eliminates the deficiency in column 3 also eliminates the deficiencies in row 2 and row 3. In general step 2 can be applied successively until all deficiencies in individual columns (rows) are removed. Frequently one can combine successive applications of step 2 into a single step with possible modification of the values to be subtracted from the rows and columns. Thus there are basically two applications of step 2 in going from C(1) to C(2) in Table 3. The second applies to column 4, indicated by a double asterisk. In determining the A for the second application, we must use the minimum of the non-zero elements of column 4