For example, if we were to take 4144 K and 3033 K as our two test temperatures, we find that
the ratio of these two temperature values is 1.3663. Raising this ratio to the fourth power gives us
3.485 for a predicted ratio of millivolt values. Multiplying the 3033 K millivoltage value of 9.9 mV
by 3.485 gives us 34.5 mV, which is quite close to the value of 34.8 mV advertised by Honeywell: