In this case we get 8 more combinations.
Now if in H2 we transpose the second row with the third one, we will again get 8 more
combinations:
If we sum up all the terms of these three combinatio ns we will have in total 24 or 4! terms, same as a 4×4 determinant has.
Thus, if we do sum these combinations we will have a 4×4 determinant solution: