where m is mass of belt per unit length in kg, ρ is density0
970 kg/m3, b width010 mm and t thickness011 mm
Therefore m ¼ 970 :01 :011 ¼ 0:11 kg=m
Tc ¼ mv2
Where v is the linear velocity of belt in m/s, Tc is
centrifugal tension in newtons
Tc ¼ 0:11 4:522 ¼ 2:25N
For maximum power T103Tc
T1 ¼ 6:75N
T1 Tc
T2 Tc
¼ eμθ ð3Þ
6:75 2:25
T2 2:25
¼ e0:122:543
T205.56 N
Therefore T106.75 N and T205.56 N
Mt ¼ T1 T2 ð Þr1
Where R is radius of the pulley 0.175 m as shown in
Fig. 2.
¼ ð6:75 5:56Þ 0:175
Mt 0.208 Nm