Case 2. m = kz/2. When the number of bins is odd and Xt1 = (kz/2), the probability that a picker first goes to bin i then goes to bin ð2m iÞ is 1/2 for the tth order; hence
Case 2. m = kz/2. When the number of bins is odd and Xt1 = (kz/2),the probability that a picker first goes to bin i then goes tobin ð2m iÞ is 1/2 for the tth order; hence