solution : Here, by symmetry, it is obvious that the field can be only perpendicular to the charged surface.Construct a “Gaussian pillbox, “ as in the figure. Clearly on flux crosses the cured surfaces, and there-fore,
solution : Here, by symmetry, it is obvious that the field can be only perpendicular to the charged surface.Construct a “Gaussian pillbox, “ as in the figure.Clearly on flux crosses the cured surfaces, and there-fore,