Let O be the circumcenter of triangle ABC. Consider the triangle OAOBOC formed by the circumcenters of the flanks. By the fact that the circumcenter is the intersection of the perpendicular bisectors of the sides, we see that OAOBOC is homothetic (parallel) to ABC, and that it bisects the squares on the sides of ABC. The distances between the corresponding sides of ABC and OAOBOC are
therefore
a 2,
b 2 and
c 2.