Example 1.28
Find the Laplace transform of
x + 0x (x − t)y(t)dt. (1.170)
Notice that the kernel depends on the difference x − t. The integral includes
f (x) = x and f (x) = y(x). The integral is the convolution product (f ∗
1 2 1
f2)(x). This means that if we take Laplace transform of each term we obtain
L{x} + L 0x (x − t)y(t)dt = L{x} + L{x}L{y(t)}. (1.171)
Using the table of Laplace transforms gives
1 1
2 + 2 Y (s). (1.172)
s s