solution : here, by symmetry, it is obvious that the field can be only perpendicular to the charged surface. Construct a gaussian pillbox. as in the figure. Clearly on flux crosses the cured surfaces, and there-fore
solution : here, by symmetry, it is obvious that the field can be only perpendicular to the charged surface.Construct a gaussian pillbox. as in the figure.Clearly on flux crosses the cured surfaces, and there-fore