Since x must satisfy both conditions, the domain of g is the intersection of the sets
(-infinity , 1) U (1 , + infinity) and [-3 , 3]
[-3 , 1) U (1 , +3]
Question 10: Find the range of
f(x) = | x - 2 | + 3
Solution to Question 10:
| x - 2 | is an absolute value and is either positive or equal to zero as x takes real values, hence
| x - 2 | >= 0
Add 3 to both sides of the above inequality to obtain
| x - 2 | + 3 >= 3
The expression on the left side of the above inequality is equal to f(x), hence
f(x) >= 3
The above inequality gives the range as the interval
[3 , + infinity)
Question 11: Find the range of
f(x) = -x 2 - 10
Solution to Question 11:
-x 2 is either negative or equal to zero as x takes real values, hence
-x 2