This research has been prepared ceramic systems. (1-x) Ba (Zr0.2Ti0.8) O3-x (Ba0.7Ca0.3) TiO3. The composition x = 0, 0.10, 0.30, 0.50 and 0.70 percent by weight. Prepared by molten salt And burned calcined at 700 - 1200 ° C and sintered at temperatures of 1000 - 1300 ° C for 3 hours at a rate of up / down the temperature 5 degrees Celsius, leading ceramic prepared to examine the structure. crystal microstructure Density Treasure dielectric coefficient and dielectric piezo
crystal structure analysis of the diffraction patterns of X-rays showed that the ceramic (1-x) Ba (Zr0.2Ti0.8) O3. -x (Ba0.7Ca0.3) TiO3 every x amount varying structure thrombosis Lockheed Coral proportions. Results from the analysis of ceramic surface with an electron microscope SEM found that when the temperature increases, the grain is a multi-angle triangles. Grain size is quite large And the addition amount of Ca ratios in each grain is a multi-angle triangle and a relatively smaller amount of Ca added to the study, when the density of the ceramic system. (1-x) Ba (Zr0.2Ti0.8) O3-x (Ba0.7Ca0.3) TiO3. Temperature rising Thus the density is increased and the experiment of the ceramic. (1-x) Ba (Zr0.2Ti0.8) O3-x (Ba0.7Ca0.3) TiO3 found that x = 0.50, with the highest density. Which is equal to 5.6 when examining the properties of the dielectric found that when the temperature increases, the dielectric constant higher. And the trial of the ceramic. (1-x) Ba (Zr0.2Ti0.8) O3-x (Ba0.7Ca0.3) TiO3 where x = 0.30 to a high dielectric constant. Which is equal to 2023 and studied at the coefficient of piezo electric ceramic systems. (1-x) Ba (Zr0.2Ti0.8) O3-x (Ba0.7Ca0.3) TiO3. Making the coefficient piezo dielectric increases with the addition of Ca increases and experimental ceramics. (1-x) Ba (Zr0.2Ti0.8) O3-x (Ba0.7Ca0.3) TiO3 found that x = 0.30 coefficient piezo dielectric most. Which is equal to 64