Therefore, the median CE bisects the median BD at a point that is two thirds of the way from B to D. Median BD bisects median CE at a point that is two-thirds of the way from C to E, and if we were to construct a median from A to a point F then the median from A to F will also cut BD at a point that is two-thirds of the way from B to D, and will intersect the centroid, G. Therefore, the three medians in a triangle must meet at a point, thus be concurrent at a point G, and this point is exactly two- thirds the distance from each vertex to the midpoint of the opposite sides. Click here for a GSP file.