% oxalate composition = w/5 x 100
Oxalate content = C2O4
2
+8H+
+MnO4
2 -
→
2CO2+4H2O+Mn+4
The reacting ions ratio is 1:1
From M1V1 = M2V2
M = molarity of KMnO4
V1 = volume of extract (oxalate)
M2 = molarity of extract
V2 = volume of KMnO4
M.W of CaCO3 → 128.08
weight of oxalate in litre = M2 x molecular weight = Xg.
Weight of oxalate titrand (2ml) =X x 2g = y 100ml of oxalate
extracted will be y/5 x 100g = W
Determination of saponin.
This was determined using the method described AOAC [12].
About 5.0g of the sample was extracted using soxhlet
extraction method. The sample was exhaustively extracted
to defat it for 3hrs and the solvent was distilled off. Another
extraction was carried out using a pre weighed flask fitted
unto the soxhlet apparatus. Methanol enough to cause a
reflux was poured into the flask to extract saponin . The
saponin was exhaustively extracted for 3hrs. The methanol
was then evaporated and the flask re-weighed. The
difference in weight is the weight of saponin extracted.
The percentage saponin is calculated below: