The elements shown in the shaded cells are the new reduced cost for the nonbasic
variables Xl> X4, and Xs. All the remaining elements are the same as in the original optimal
tableau. The new optimum solution is then determined by letting Xl enter and X6
leave, which yields Xl = 10, X2 = 102.5, X3 = 215, and z = $1227.50 (verify!). Although
the new solution recommends the production of all three toys, the optimum
revenue is less than when two toys only are manufactured.