where, ka, is volumetric mass transfer coefficient. To solve Eq. (4)
by integration, following condition was used where the mass of
coconut waste oil is zero in liquid (WA) at the beginning of the
extraction process. Considering this condition, integration of Eq.
(4) resulted as:
WA ¼ WAi½1 expðkatÞ ð5Þ
Rearranging Eq. (5) in terms of yield per mass of coconut waste,
the kinetic model used in this study was:
YA ¼ YAi½1 expðkatÞ ð6Þ
where, YA and YAi is yield of coconut waste oil in liquid at time, t, s
and ka-volumetric mass transfer coefficient.
To determine the value of ka (s1), YA and YAi a nonlinear least
square method was used to calculate numerically. ‘‘Origin 8.5’’ Program
was used to fit the data in order to obtain the mass transfer
value and the yield of oil.
where, ka, is volumetric mass transfer coefficient. To solve Eq. (4)by integration, following condition was used where the mass ofcoconut waste oil is zero in liquid (WA) at the beginning of theextraction process. Considering this condition, integration of Eq.(4) resulted as:WA ¼ WAi½1 expðkatÞ ð5ÞRearranging Eq. (5) in terms of yield per mass of coconut waste,the kinetic model used in this study was:YA ¼ YAi½1 expðkatÞ ð6Þwhere, YA and YAi is yield of coconut waste oil in liquid at time, t, sand ka-volumetric mass transfer coefficient.To determine the value of ka (s1), YA and YAi a nonlinear leastsquare method was used to calculate numerically. ‘‘Origin 8.5’’ Programwas used to fit the data in order to obtain the mass transfervalue and the yield of oil.
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