The current-path though the two transistors consists of junction-drops. The path is as follows: Emitter-base of Q2 then collector-emitter of Q1. The first junction-drop is 0.7v. The second drop is normally 0.2v. The supply is 3v. There is no resistor to take up the excess voltage.
What happens is this: Q1 does not turn on fully and the voltage across collector-emitter is 2.3v.
Since Q1 is turned on very lightly, the collector-emitter current will be less than 1mA.
Q2 will amplify this current 100 times and the current through the LEDs could be as high as 50mA each.
There is no current-limiting for the LEDs.