Finally,if the secondary key are unique,each list will have a length of one , and a separate linked list will exist for every record in the database. Because this situation is unworkable,linked lists cannot beused for unique keys. For example,suppose that the CUSTOMER records contain another unique field,say,social security number.If we attempt to represent this unique secondary key using a linked list, every socail security number will be a separate list. furthermore, each linked list will have just one item in it: the single record having the indicated socail security number.