That total value to you will be the sum of the decreasing 1/ k values of all the other members of the network. So if your network has n members, this value will be proportional to 1 + 1/2 + 1/3 +… + 1/( n –1), which approaches log( n ). More precisely, it will almost equal the sum of log( n ) plus a constant value. Of course, there are n -1 other members who derive similar value from the network, so the value to all n of you increases as n log( n ).