Considering the 1H and 13C NMR data of L, in DMSO-d6, clearly
realizes that both dipic2 and MetH+ are present in L. The 1H NMR
shows three resonances from which the one at 7.8 ppm is assigned
to dipic2 and the remaining two resonances correspond to MetH+.
In the 13C NMR spectrum, four signals at 124.8, 137.7, 154.3 and
196.8 ppm out of the seven totals could definitely be assigned to
the dipic2 and another three peaks can be assigned to carbon
atoms of MetH+. From the number resonances in both spectra
and the integration of the 1H resonances, it can be concluded that
L consists of both MetH+ and dipic2 fragments, respectively